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CGP EDU Academic Team
Published on: August 13, 2026
The real number k for which the equation, 2x 3 + 3x + k = 0 has two distinct real roots in [0, 1]
Text Solution
Verified by ExpertsThe correct answer is:
D
f(x) = 2x 3 + 3x + k
f ′ (x) = 6x 2 + 3 > 0 ∀ x ∈ R
⇒ f(x) is strictly increasing function
⇒ f(x) = 0 has only one real root, so two roots are not possible
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